0.2x^2=13

Solution for 0.2x^2=13 equation:

0.2x^2=13

We move all terms to the left:

0.2x^2-(13)=0

a = 0.2; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·0.2·(-13)
Δ = 10.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10.4}}{2*0.2}=\frac{0-\sqrt{10.4}}{0.4}
=-\frac{\sqrt{}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10.4}}{2*0.2}=\frac{0+\sqrt{10.4}}{0.4}
=\frac{\sqrt{}}{0.4}
$